-16x^2+1936=1100

Solution for -16x^2+1936=1100 equation:

-16x^2+1936=1100

We move all terms to the left:

-16x^2+1936-(1100)=0

We add all the numbers together, and all the variables

-16x^2+836=0

a = -16; b = 0; c = +836;
Δ = b2-4ac
Δ = 02-4·(-16)·836
Δ = 53504
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{53504}=\sqrt{256*209}=\sqrt{256}*\sqrt{209}=16\sqrt{209}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-16\sqrt{209}}{2*-16}=\frac{0-16\sqrt{209}}{-32}
=-\frac{16\sqrt{209}}{-32}
=-\frac{\sqrt{209}}{-2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+16\sqrt{209}}{2*-16}=\frac{0+16\sqrt{209}}{-32}
=\frac{16\sqrt{209}}{-32}
=\frac{\sqrt{209}}{-2}
$